什么是 android 用数组替换 $.ajax

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What is android replacement for $.ajax with array

本问题已经有最佳答案，请猛点这里访问。

我有现有的 jquery 代码可以在登录过程中将数组 \\'array\\' 作为 json var 提交

var array1 = {

"command" :"login",

"username": $("#txt_username").val(),

"password": $("#txt_password").val(),

"remember": $('#chk_remember').is(':checked')

};



$.ajax({

        url: 'functions.php',

        data : {'array': array1},

        dataType: 'json',

        type: 'POST',

        success: function(data) {

          if (data.success == 1 ){



         $('#result').html("You have been logged in.</br>You will be   redirected to another page");

}

});

if (isset($_POST["array"])) {

$array = $_POST['array'];

switch ($array["command"]) {

  case"login" :

    if (DoLogin($array["username"], $array["password"]) == true) {

      $success = 1;

}

    else {

      $success = 0;

    }

    $arr = array("success" => $success,"redirect" => 1);



    echo json_encode($arr);

break;

}
public class Utils {



  public static String POST(String url, Login login){

    InputStream inputStream = null;

    String result ="";

    try {



      // 1. create HttpClient

      HttpClient httpclient = new DefaultHttpClient();



      // 2. make POST request to the given URL

      HttpPost httpPost = new HttpPost(url);



      String json ="";



      // 3. build jsonObject

      JSONObject jsonObject = new JSONObject();

      jsonObject.accumulate("command", login.command);

      jsonObject.accumulate("username", login.username);

      jsonObject.accumulate("password", login.password);

      jsonObject.accumulate("remember", login.remember);



      // 4. convert JSONObject to JSON to String

      json = jsonObject.toString();



      // ** Alternative way to convert Login object to JSON string usin Jackson Lib

      // ObjectMapper mapper = new ObjectMapper();

      // json = mapper.writeValueAsString(login);



      // 5. set json to StringEntity

      StringEntity se = new StringEntity(json);



      // 6. set httpPost Entity

      httpPost.setEntity(se);



      // 7. Set some headers to inform server about the type of the content

      httpPost.setHeader("Accept","application/json");

      httpPost.setHeader("Content-type","application/json");



      // 8. Execute POST request to the given URL

      HttpResponse httpResponse = httpclient.execute(httpPost);



      // 9. receive response as inputStream

      inputStream = httpResponse.getEntity().getContent();



      // 10. convert inputstream to string

      if(inputStream != null)

      result = convertInputStreamToString(inputStream);

      else

      result ="Did not work!";



      } catch (Exception e) {

      Log.d("InputStream", e.getLocalizedMessage());

    }



    // 11. return result

    return result;

  }

}



// Model login obj

public class Login {

  public String password;

  public String username;

  public String command;

  public boolean remember;

}
Login login = new Login();



// get reference to the views

login.username = (EditText) findViewById(R.id.user);

login.password = (EditText) findViewById(R.id.pass);

login.command = (EditText) findViewById(R.id.comm);

login.remember = ((CheckBox) findViewById(R.id.rem)).isChecked();



Utils.POST(stringUrl, login) // use AsynckTask for this http://stackoverflow.com/questions/8829135/android-http-request-asynctask

在 PHP

var array1 = {

"command" :"login",

"username": $("#txt_username").val(),

"password": $("#txt_password").val(),

"remember": $('#chk_remember').is(':checked')

};



$.ajax({

        url: 'functions.php',

        data : {'array': array1},

        dataType: 'json',

        type: 'POST',

        success: function(data) {

          if (data.success == 1 ){



         $('#result').html("You have been logged in.</br>You will be   redirected to another page");

}

});

if (isset($_POST["array"])) {

$array = $_POST['array'];

switch ($array["command"]) {

  case"login" :

    if (DoLogin($array["username"], $array["password"]) == true) {

      $success = 1;

}

    else {

      $success = 0;

    }

    $arr = array("success" => $success,"redirect" => 1);



    echo json_encode($arr);

break;

}
public class Utils {



  public static String POST(String url, Login login){

    InputStream inputStream = null;

    String result ="";

    try {



      // 1. create HttpClient

      HttpClient httpclient = new DefaultHttpClient();



      // 2. make POST request to the given URL

      HttpPost httpPost = new HttpPost(url);



      String json ="";



      // 3. build jsonObject

      JSONObject jsonObject = new JSONObject();

      jsonObject.accumulate("command", login.command);

      jsonObject.accumulate("username", login.username);

      jsonObject.accumulate("password", login.password);

      jsonObject.accumulate("remember", login.remember);



      // 4. convert JSONObject to JSON to String

      json = jsonObject.toString();



      // ** Alternative way to convert Login object to JSON string usin Jackson Lib

      // ObjectMapper mapper = new ObjectMapper();

      // json = mapper.writeValueAsString(login);



      // 5. set json to StringEntity

      StringEntity se = new StringEntity(json);



      // 6. set httpPost Entity

      httpPost.setEntity(se);



      // 7. Set some headers to inform server about the type of the content

      httpPost.setHeader("Accept","application/json");

      httpPost.setHeader("Content-type","application/json");



      // 8. Execute POST request to the given URL

      HttpResponse httpResponse = httpclient.execute(httpPost);



      // 9. receive response as inputStream

      inputStream = httpResponse.getEntity().getContent();



      // 10. convert inputstream to string

      if(inputStream != null)

      result = convertInputStreamToString(inputStream);

      else

      result ="Did not work!";



      } catch (Exception e) {

      Log.d("InputStream", e.getLocalizedMessage());

    }



    // 11. return result

    return result;

  }

}



// Model login obj

public class Login {

  public String password;

  public String username;

  public String command;

  public boolean remember;

}
Login login = new Login();



// get reference to the views

login.username = (EditText) findViewById(R.id.user);

login.password = (EditText) findViewById(R.id.pass);

login.command = (EditText) findViewById(R.id.comm);

login.remember = ((CheckBox) findViewById(R.id.rem)).isChecked();



Utils.POST(stringUrl, login) // use AsynckTask for this http://stackoverflow.com/questions/8829135/android-http-request-asynctask

如何处理来自android的这个登录过程？

var array1 = {

"command" :"login",

"username": $("#txt_username").val(),

"password": $("#txt_password").val(),

"remember": $('#chk_remember').is(':checked')

};



$.ajax({

        url: 'functions.php',

        data : {'array': array1},

        dataType: 'json',

        type: 'POST',

        success: function(data) {

          if (data.success == 1 ){



         $('#result').html("You have been logged in.</br>You will be   redirected to another page");

}

});

if (isset($_POST["array"])) {

$array = $_POST['array'];

switch ($array["command"]) {

  case"login" :

    if (DoLogin($array["username"], $array["password"]) == true) {

      $success = 1;

}

    else {

      $success = 0;

    }

    $arr = array("success" => $success,"redirect" => 1);



    echo json_encode($arr);

break;

}
public class Utils {



  public static String POST(String url, Login login){

    InputStream inputStream = null;

    String result ="";

    try {



      // 1. create HttpClient

      HttpClient httpclient = new DefaultHttpClient();



      // 2. make POST request to the given URL

      HttpPost httpPost = new HttpPost(url);



      String json ="";



      // 3. build jsonObject

      JSONObject jsonObject = new JSONObject();

      jsonObject.accumulate("command", login.command);

      jsonObject.accumulate("username", login.username);

      jsonObject.accumulate("password", login.password);

      jsonObject.accumulate("remember", login.remember);



      // 4. convert JSONObject to JSON to String

      json = jsonObject.toString();



      // ** Alternative way to convert Login object to JSON string usin Jackson Lib

      // ObjectMapper mapper = new ObjectMapper();

      // json = mapper.writeValueAsString(login);



      // 5. set json to StringEntity

      StringEntity se = new StringEntity(json);



      // 6. set httpPost Entity

      httpPost.setEntity(se);



      // 7. Set some headers to inform server about the type of the content

      httpPost.setHeader("Accept","application/json");

      httpPost.setHeader("Content-type","application/json");



      // 8. Execute POST request to the given URL

      HttpResponse httpResponse = httpclient.execute(httpPost);



      // 9. receive response as inputStream

      inputStream = httpResponse.getEntity().getContent();



      // 10. convert inputstream to string

      if(inputStream != null)

      result = convertInputStreamToString(inputStream);

      else

      result ="Did not work!";



      } catch (Exception e) {

      Log.d("InputStream", e.getLocalizedMessage());

    }



    // 11. return result

    return result;

  }

}



// Model login obj

public class Login {

  public String password;

  public String username;

  public String command;

  public boolean remember;

}
Login login = new Login();



// get reference to the views

login.username = (EditText) findViewById(R.id.user);

login.password = (EditText) findViewById(R.id.pass);

login.command = (EditText) findViewById(R.id.comm);

login.remember = ((CheckBox) findViewById(R.id.rem)).isChecked();



Utils.POST(stringUrl, login) // use AsynckTask for this http://stackoverflow.com/questions/8829135/android-http-request-asynctask

进入活动

var array1 = {

"command" :"login",

"username": $("#txt_username").val(),

"password": $("#txt_password").val(),

"remember": $('#chk_remember').is(':checked')

};



$.ajax({

        url: 'functions.php',

        data : {'array': array1},

        dataType: 'json',

        type: 'POST',

        success: function(data) {

          if (data.success == 1 ){



         $('#result').html("You have been logged in.</br>You will be   redirected to another page");

}

});

if (isset($_POST["array"])) {

$array = $_POST['array'];

switch ($array["command"]) {

  case"login" :

    if (DoLogin($array["username"], $array["password"]) == true) {

      $success = 1;

}

    else {

      $success = 0;

    }

    $arr = array("success" => $success,"redirect" => 1);



    echo json_encode($arr);

break;

}
public class Utils {



  public static String POST(String url, Login login){

    InputStream inputStream = null;

    String result ="";

    try {



      // 1. create HttpClient

      HttpClient httpclient = new DefaultHttpClient();



      // 2. make POST request to the given URL

      HttpPost httpPost = new HttpPost(url);



      String json ="";



      // 3. build jsonObject

      JSONObject jsonObject = new JSONObject();

      jsonObject.accumulate("command", login.command);

      jsonObject.accumulate("username", login.username);

      jsonObject.accumulate("password", login.password);

      jsonObject.accumulate("remember", login.remember);



      // 4. convert JSONObject to JSON to String

      json = jsonObject.toString();



      // ** Alternative way to convert Login object to JSON string usin Jackson Lib

      // ObjectMapper mapper = new ObjectMapper();

      // json = mapper.writeValueAsString(login);



      // 5. set json to StringEntity

      StringEntity se = new StringEntity(json);



      // 6. set httpPost Entity

      httpPost.setEntity(se);



      // 7. Set some headers to inform server about the type of the content

      httpPost.setHeader("Accept","application/json");

      httpPost.setHeader("Content-type","application/json");



      // 8. Execute POST request to the given URL

      HttpResponse httpResponse = httpclient.execute(httpPost);



      // 9. receive response as inputStream

      inputStream = httpResponse.getEntity().getContent();



      // 10. convert inputstream to string

      if(inputStream != null)

      result = convertInputStreamToString(inputStream);

      else

      result ="Did not work!";



      } catch (Exception e) {

      Log.d("InputStream", e.getLocalizedMessage());

    }



    // 11. return result

    return result;

  }

}



// Model login obj

public class Login {

  public String password;

  public String username;

  public String command;

  public boolean remember;

}
Login login = new Login();



// get reference to the views

login.username = (EditText) findViewById(R.id.user);

login.password = (EditText) findViewById(R.id.pass);

login.command = (EditText) findViewById(R.id.comm);

login.remember = ((CheckBox) findViewById(R.id.rem)).isChecked();



Utils.POST(stringUrl, login) // use AsynckTask for this http://stackoverflow.com/questions/8829135/android-http-request-asynctask

我建议研究使用 Volley 来处理您的网络请求。这是一个方便的入门指南：http://www.androidhive.info/2014/05/android-working-with-volley-library-1/

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