拆分字符串然后按字符数拆分

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Splitting a string then splitting by character number

我有一个包含许多行的信息文件，其中一些行上有一组数据对。我想提取深度和温度对。这些对在字符 64 之后开始，每对占据 17 个字符的空间。

我目前正在做的是在字符 64 处截断字符串(python 计数为 63)，然后每隔 17 个字符分割字符串。

如果对之间有空白，这很好用，但是有些对没有，因为深度很大。

以下是示例：

'  1.9901 954.01'

'  1.43011675.01'

import os, re

import string



with open('TE_feb_2014.pos','r') as file:

 for line in file:

  m = re.search('(TEMP01)', line)

  if m:

   values = string.split(line[63:])

   #print values

   n = 17

   [values[i:i+n] for i in range(0, len(values), n)]

   print values
00087501 297017Q990066614201402251006TE    42550TEMP01 18D  2.01  -1.2801 50.01  -1.1601 99.01  -0.5901 148.01  -0.8001 197.01  -1.1001 245.01  -1.7501 295.01  -1.7701 301.01  -1.7801 343.01  -1.7301 392.01  -1.6701 441.01  -1.5901 489.01  -1.4501 538.01  -1.1401 587.01  -0.7201 635.01  -0.3201 684.01  0.3501 731.01  0.6201 733.01  0.6201

>>> import re

>>> s ="00087501 297017Q990066614201402251006TE    42550TEMP01 18D  2.01  -1.2801 50.01  -1.1601 99.01  -0.5901 148.01  -0.8001 197.01  -1.1001 245.01  -1.7501 295.01  -1.7701 301.01  -1.7801 343.01  -1.7301 392.01  -1.6701 441.01  -1.5901 489.01  -1.4501 538.01  -1.1401 587.01  -0.7201 635.01  -0.3201 684.01  0.3501 731.01  0.6201 733.01  0.6201"

>>> m = re.sub(r'^.{64}', r'', s)  # To remove the first 64 characters from the input string.

>>> re.findall(r'.{1,17}', m)    # To find all the matches which has the maximum of 17 characters and a minimum of `1` character.

[' 2.01  -1.2801 ', ' 50.01  -1.1601 ', ' 99.01  -0.5901 ', '148.01  -0.8001 ', '197.01  -1.1001 ', '245.01  -1.7501 ', '295.01  -1.7701 ', '301.01  -1.7801 ', '343.01  -1.7301 ', '392.01  -1.6701 ', '441.01  -1.5901 ', '489.01  -1.4501 ', '538.01  -1.1401 ', '587.01  -0.7201 ', '635.01  -0.3201 ', '684.01  0.3501 ', '731.01  0.6201 ', '733.01  0.6201']

>>> for i in re.findall(r'.{1,17}', m):

    print(i)





 2.01  -1.2801 

50.01  -1.1601 

99.01  -0.5901 

148.01  -0.8001 

197.01  -1.1001 

245.01  -1.7501 

295.01  -1.7701 

301.01  -1.7801 

343.01  -1.7301 

392.01  -1.6701 

441.01  -1.5901 

489.01  -1.4501 

538.01  -1.1401 

587.01  -0.7201 

635.01  -0.3201 

684.01  0.3501 

731.01  0.6201 

733.01  0.6201

temp 占据前 10 个字符，depth 占据接下来的 7 个字符。所以我想做的是拆分行，这样我可以分别提取所有值，然后将它们配对。

但是，我在创建增量为 7 或 10 的拆分时遇到问题。此外，我不确定 python 将字符串转换为列表并保留字符长度会发生什么。

这是我的工作代码：

'  1.9901 954.01'

'  1.43011675.01'

import os, re

import string



with open('TE_feb_2014.pos','r') as file:

 for line in file:

  m = re.search('(TEMP01)', line)

  if m:

   values = string.split(line[63:])

   #print values

   n = 17

   [values[i:i+n] for i in range(0, len(values), n)]

   print values
00087501 297017Q990066614201402251006TE    42550TEMP01 18D  2.01  -1.2801 50.01  -1.1601 99.01  -0.5901 148.01  -0.8001 197.01  -1.1001 245.01  -1.7501 295.01  -1.7701 301.01  -1.7801 343.01  -1.7301 392.01  -1.6701 441.01  -1.5901 489.01  -1.4501 538.01  -1.1401 587.01  -0.7201 635.01  -0.3201 684.01  0.3501 731.01  0.6201 733.01  0.6201

>>> import re

>>> s ="00087501 297017Q990066614201402251006TE    42550TEMP01 18D  2.01  -1.2801 50.01  -1.1601 99.01  -0.5901 148.01  -0.8001 197.01  -1.1001 245.01  -1.7501 295.01  -1.7701 301.01  -1.7801 343.01  -1.7301 392.01  -1.6701 441.01  -1.5901 489.01  -1.4501 538.01  -1.1401 587.01  -0.7201 635.01  -0.3201 684.01  0.3501 731.01  0.6201 733.01  0.6201"

>>> m = re.sub(r'^.{64}', r'', s)  # To remove the first 64 characters from the input string.

>>> re.findall(r'.{1,17}', m)    # To find all the matches which has the maximum of 17 characters and a minimum of `1` character.

[' 2.01  -1.2801 ', ' 50.01  -1.1601 ', ' 99.01  -0.5901 ', '148.01  -0.8001 ', '197.01  -1.1001 ', '245.01  -1.7501 ', '295.01  -1.7701 ', '301.01  -1.7801 ', '343.01  -1.7301 ', '392.01  -1.6701 ', '441.01  -1.5901 ', '489.01  -1.4501 ', '538.01  -1.1401 ', '587.01  -0.7201 ', '635.01  -0.3201 ', '684.01  0.3501 ', '731.01  0.6201 ', '733.01  0.6201']

>>> for i in re.findall(r'.{1,17}', m):

    print(i)





 2.01  -1.2801 

50.01  -1.1601 

99.01  -0.5901 

148.01  -0.8001 

197.01  -1.1001 

245.01  -1.7501 

295.01  -1.7701 

301.01  -1.7801 

343.01  -1.7301 

392.01  -1.6701 

441.01  -1.5901 

489.01  -1.4501 

538.01  -1.1401 

587.01  -0.7201 

635.01  -0.3201 

684.01  0.3501 

731.01  0.6201 

733.01  0.6201

这是一个示例数据线(没有上述问题)：

'  1.9901 954.01'

'  1.43011675.01'

import os, re

import string



with open('TE_feb_2014.pos','r') as file:

 for line in file:

  m = re.search('(TEMP01)', line)

  if m:

   values = string.split(line[63:])

   #print values

   n = 17

   [values[i:i+n] for i in range(0, len(values), n)]

   print values
00087501 297017Q990066614201402251006TE    42550TEMP01 18D  2.01  -1.2801 50.01  -1.1601 99.01  -0.5901 148.01  -0.8001 197.01  -1.1001 245.01  -1.7501 295.01  -1.7701 301.01  -1.7801 343.01  -1.7301 392.01  -1.6701 441.01  -1.5901 489.01  -1.4501 538.01  -1.1401 587.01  -0.7201 635.01  -0.3201 684.01  0.3501 731.01  0.6201 733.01  0.6201

>>> import re

>>> s ="00087501 297017Q990066614201402251006TE    42550TEMP01 18D  2.01  -1.2801 50.01  -1.1601 99.01  -0.5901 148.01  -0.8001 197.01  -1.1001 245.01  -1.7501 295.01  -1.7701 301.01  -1.7801 343.01  -1.7301 392.01  -1.6701 441.01  -1.5901 489.01  -1.4501 538.01  -1.1401 587.01  -0.7201 635.01  -0.3201 684.01  0.3501 731.01  0.6201 733.01  0.6201"

>>> m = re.sub(r'^.{64}', r'', s)  # To remove the first 64 characters from the input string.

>>> re.findall(r'.{1,17}', m)    # To find all the matches which has the maximum of 17 characters and a minimum of `1` character.

[' 2.01  -1.2801 ', ' 50.01  -1.1601 ', ' 99.01  -0.5901 ', '148.01  -0.8001 ', '197.01  -1.1001 ', '245.01  -1.7501 ', '295.01  -1.7701 ', '301.01  -1.7801 ', '343.01  -1.7301 ', '392.01  -1.6701 ', '441.01  -1.5901 ', '489.01  -1.4501 ', '538.01  -1.1401 ', '587.01  -0.7201 ', '635.01  -0.3201 ', '684.01  0.3501 ', '731.01  0.6201 ', '733.01  0.6201']

>>> for i in re.findall(r'.{1,17}', m):

    print(i)





 2.01  -1.2801 

50.01  -1.1601 

99.01  -0.5901 

148.01  -0.8001 

197.01  -1.1001 

245.01  -1.7501 

295.01  -1.7701 

301.01  -1.7801 

343.01  -1.7301 

392.01  -1.6701 

441.01  -1.5901 

489.01  -1.4501 

538.01  -1.1401 

587.01  -0.7201 

635.01  -0.3201 

684.01  0.3501 

731.01  0.6201 

733.01  0.6201

好像你想要这样的东西，

'  1.9901 954.01'

'  1.43011675.01'

import os, re

import string



with open('TE_feb_2014.pos','r') as file:

 for line in file:

  m = re.search('(TEMP01)', line)

  if m:

   values = string.split(line[63:])

   #print values

   n = 17

   [values[i:i+n] for i in range(0, len(values), n)]

   print values
00087501 297017Q990066614201402251006TE    42550TEMP01 18D  2.01  -1.2801 50.01  -1.1601 99.01  -0.5901 148.01  -0.8001 197.01  -1.1001 245.01  -1.7501 295.01  -1.7701 301.01  -1.7801 343.01  -1.7301 392.01  -1.6701 441.01  -1.5901 489.01  -1.4501 538.01  -1.1401 587.01  -0.7201 635.01  -0.3201 684.01  0.3501 731.01  0.6201 733.01  0.6201

>>> import re

>>> s ="00087501 297017Q990066614201402251006TE    42550TEMP01 18D  2.01  -1.2801 50.01  -1.1601 99.01  -0.5901 148.01  -0.8001 197.01  -1.1001 245.01  -1.7501 295.01  -1.7701 301.01  -1.7801 343.01  -1.7301 392.01  -1.6701 441.01  -1.5901 489.01  -1.4501 538.01  -1.1401 587.01  -0.7201 635.01  -0.3201 684.01  0.3501 731.01  0.6201 733.01  0.6201"

>>> m = re.sub(r'^.{64}', r'', s)  # To remove the first 64 characters from the input string.

>>> re.findall(r'.{1,17}', m)    # To find all the matches which has the maximum of 17 characters and a minimum of `1` character.

[' 2.01  -1.2801 ', ' 50.01  -1.1601 ', ' 99.01  -0.5901 ', '148.01  -0.8001 ', '197.01  -1.1001 ', '245.01  -1.7501 ', '295.01  -1.7701 ', '301.01  -1.7801 ', '343.01  -1.7301 ', '392.01  -1.6701 ', '441.01  -1.5901 ', '489.01  -1.4501 ', '538.01  -1.1401 ', '587.01  -0.7201 ', '635.01  -0.3201 ', '684.01  0.3501 ', '731.01  0.6201 ', '733.01  0.6201']

>>> for i in re.findall(r'.{1,17}', m):

    print(i)





 2.01  -1.2801 

50.01  -1.1601 

99.01  -0.5901 

148.01  -0.8001 

197.01  -1.1001 

245.01  -1.7501 

295.01  -1.7701 

301.01  -1.7801 

343.01  -1.7301 

392.01  -1.6701 

441.01  -1.5901 

489.01  -1.4501 

538.01  -1.1401 

587.01  -0.7201 

635.01  -0.3201 

684.01  0.3501 

731.01  0.6201 

733.01  0.6201
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